Solutions Manual
INTRODUCTION TO MECHATRONICS AND MEASUREMENT SYSTEMS 4th edition 2012(c)
SOLUTIONS MANUAL David G. Alciatore and Michael B. Histand
Department of Mechanical Engineering Colorado State University Fort Collins, CO 80523
Introduction to Mechatronics and Measurement Systems
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Solutions Manual
This manual contains solutions to the end-of-chapter problems in the third edition of "Introduction to Mechatronics and Measurement Systems." Only a few of the open-ended problems that do not have a unique answer are left for your creative solutions. More information, including an example course outline, a suggested laboratory syllabus, MathCAD files for examples in the book, and other supplemental material are provided on the Internet at: mechatronics.colostate.edu We have class-tested the textbook for several years, and it should be relatively free from errors. However, if you notice any errors or have suggestions or advice concerning the textbook's content or approach, please feel free to contact us via e-mail at
[email protected] We will post corrections for reported errors on our Web site. Thank you for choosing our book. We hope it helps you provide your students with an enjoyable and fruitful learning experience in the cross-disciplinary subject of mechatronics.
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Introduction to Mechatronics and Measurement Systems
Solutions Manual 2.1
D = 0.06408 in = 0.001628 m. 2
–6 A = D ---------- = 2.082 10 4
= 1.7 x 10-8 m, L = 1000 m R = L ------- = 8.2 A 2.2 4
(a)
R 1 = 21 10 20% so 168k R 1 252k
(b)
R 2 = 07 10 20% so 5.6k R 2 8.4k
(c)
R s = R 1 + R 2 = 217k 20% so 174k R s 260k
(d)
R1 R2 R p = -----------------R1 + R2
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R 1MIN R 2MIN R pMIN = ------------------------------- = 5.43k R 1MIN + R 2 MIN R 1MAX R 2MAX R pMAX = --------------------------------- = 8.14k R 1 MAX + R 2 MAX 2.3
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R 1 = 10 10 , R 2 = 25 10
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2 1 R1 R2 1 25 10 10 10 R = ------------------- = --------------------------------------------------- = 20 10 2 1 R1 + R2 10 10 + 25 10
a = 2 = red, b = 0 = black, c = 1 = brown, d = gold 2.4
In series, the trim pot will add an adjustable value ranging from 0 to its maximum value to the original resistor value depending on the trim setting. When in parallel, the trim pot could be 0 perhaps causing a short. Furthermore, the trim value will not be additive with the fixed resistor.
2.5
When the last connection is made, a spark occurs at the point of connection as the completed circuit is formed. This spark could ignite gases produced in the battery. The negative terminal of the battery is connected to the frame of the car, which serves as a ground reference throughout the vehicle.
Introduction to Mechatronics and Measurement Systems
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Solutions Manual 2.6
No, as long as you are consistent in your application, you will obtain correct answers. If you assume the wrong current direction, the result will be negative.
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